Home Backend Development Golang How to Efficiently Implement a Save Method Across Dissimilar Go Structs with Shared Fields?

How to Efficiently Implement a Save Method Across Dissimilar Go Structs with Shared Fields?

Nov 20, 2024 pm 12:56 PM

How to Efficiently Implement a Save Method Across Dissimilar Go Structs with Shared Fields?

How to Append a Save Method to Dissimilar Structs with Shared Fields

Consider the following context:

type ModelA struct {
    Guid string `orm:"pk"`
    FiledA string
}

type ModelB struct {
    Guid string `orm:"pk"`
    FiledB string
}
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The need arose to introduce a Save() method for both structs (ModelA and ModelB). While it's possible to create a common base struct and embed it into ModelA and ModelB, this approach is not viable due to ORM limitations.

Alternative Approach: Implementing an Interface

Designate a common interface for saving data, such as Savable, as seen below:

type Savable interface {
   Save()
}
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Implement the Save() method for each struct, ensuring that they satisfy the Savable interface:

func (a ModelA) Save() {
   // Save logic for ModelA
}

func (b ModelB) Save() {
   // Save logic for ModelB
}
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With this structure in place, you can operate on instances of either struct through the Savable interface:

var i Savable
i = SomeMethodThatRetunsMyModel()
i.Save()
SomeOthermMethodThatAcceptsASavableAndCallesSave(i)
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Implementation Using Embedding

Alternatively, you can also opt for an embedding approach by defining a base ModelC with the common field (Guid):

type ModelA struct {
   ModelC
   FiledA string
}

type ModelB struct {
   ModelC
   FiledB string
}

type ModelC struct {
   Guid string `orm:"pk"`
}

func (c ModelC) Save() error {
   // Save logic for ModelC
   return nil
}
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However, note that this method will only save fields defined in ModelC.

Considerations

It's important to note the limitations of both approaches:

  • The embedding approach may not be suitable if you need to statically reference embedded types.
  • The interface approach provides more flexibility but may result in code duplication.

Ultimately, the best solution depends on the specific requirements of your application.

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