How to Deserialize JSON with Dynamic Names in Nested Structures in Go?

Decoding Nested Dynamic Structures in JSON with Go

This article addresses the challenge of deserializing JSON data that features dynamic names within nested structures. Let's examine the problem and provide a solution.

Problem Statement

Consider the following JSON response:

{
    "status": "OK",
    "status_code": 100,
    "sms": {
        "79607891234": {
            "status": "ERROR",
            "status_code": 203,
            "status_text": "Нет текста сообщения"
        },
        "79035671233": {
            "status": "ERROR",
            "status_code": 203,
            "status_text": "Нет текста сообщения"
        },
        "79105432212": {
            "status": "ERROR",
            "status_code": 203,
            "status_text": "Нет текста сообщения"
        }
    },
    "balance": 2676.18
}

struct:

type SMSPhone struct {
    Status     string `json:"status"`
    StatusCode int    `json:"status_code"`
    StatusText string `json:"status_text"`
}

type SMSSendJSON struct {
    Status     string     `json:"status"`
    StatusCode int        `json:"status_code"`
    Sms        []SMSPhone `json:"sms"`
    Balance    float64    `json:"balance"`
}

The issue arises due to the dynamic phone numbers as property names within the "sms" object.

Solution

To handle this situation, we can utilize a map to represent the "sms" object in JSON:

type SMSPhone struct {
    Status     string `json:"status"`
    StatusCode int    `json:"status_code"`
    StatusText string `json:"status_text"`
}

type SMSSendJSON struct {
    Status     string              `json:"status"`
    StatusCode int                 `json:"status_code"`
    Sms        map[string]SMSPhone `json:"sms"`
    Balance    float64             `json:"balance"`
}

Now, the deserialization code looks like this:

var result SMSSendJSON

if err := json.Unmarshal([]byte(src), &result); err != nil {
    panic(err)
}

This approach allows us to correctly process nested dynamic structures in Go.

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