Casting Integers to Floats for Accurate Division
In C , dividing two integers, such as in a/b, results in an integer quotient. To obtain a float result, one must specifically cast the operands to floats.
Problem Statement:
When using integer operands in a division operation, the result is truncated to an integer. How can one prevent this and maintain the integrity of the numbers?
Solution:
To remedy this issue and ensure a float result, cast the operands to floats:
float ans = (float)a / (float)b;
By explicitly converting the operands to floats, the division operation will produce a float result, preserving any decimal precision.
Example:
Consider the following code:
#include <iostream> #include <iomanip> using namespace std; int main() { int a = 10, b = 3; float ans = (float)a / (float)b; cout << fixed << setprecision(3); cout << (a/b) << endl; cout << ans << endl; return 0; }
Output:
3 3.333
As seen above, the casting ensures a float result, retaining the correct decimal precision.
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