How to Differentiate Embedded `\\n` from Actual Line Breaks in Go String Output?

Handling String Differentiation in Go

When dealing with string output generated by a Linux command in Go, differentiating between embedded "n" characters and actual line breaks can be challenging, potentially leading to incorrect string parsing.

In the scenario described, the goal is to distinguish between "n" characters present within a multi-line string (representing quoted strings) and actual line breaks that separate different result lines.

To address this issue, consider the following technique:

output := strings.Replace(sourceStr, `\n`, "\n", -1)

This code replaces all instances of escaped "n" characters (i.e., n) with actual line breaks "n."

String literals inside backticks () in Go allow for multi-line strings. However, when processing these strings in the code, line breaks are escaped with n`. By replacing these escaped line breaks with actual line breaks, you can differentiate between embedded "n" characters and actual line separators.

This approach ensures that subsequent string parsing techniques, such as strings.Split or bufio.NewScanner, will behave correctly, breaking the multi-line string into individual lines based on actual line breaks rather than embedded "n" characters.

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