How Can We Print Numbers Sequentially Without Loops or Conditional Statements?

Printing Numbers Without Loops or Conditionals

In programming, it is often necessary to print or display a sequence of numbers. A common approach is to use loops or conditional statements to iterate through the desired range. However, it is possible to print a series of numbers without relying on these constructs.

Printing from 1 to 1000 in C or C

For the task of printing numbers from 1 to 1000, one possible solution involves a recursive function:

#include <stdio.h>

void main(int j) {
  printf("%d\n", j);
  (&&main + (&exit - &main)*(j/1000))(j+1);
}

This function calls itself recursively, incrementing the parameter j until it reaches the value of 1000. To avoid pointer errors, the address-of operator & is used before the function pointer.

Standard C Version

A more standard C version of the above function is as follows:

#include <stdio.h>
#include <stdlib.h>

void f(int j) {
  static void (*const ft[2])(int) = { f, exit };

  printf("%d\n", j);
  ft[j/1000](j + 1);
}

int main(int argc, char *argv[]) {
  f(1);
}

This version uses a static function pointer array to achieve the same effect.

Conclusion

While these methods may not be the most efficient or elegant solutions, they demonstrate the possibility of printing sequences of numbers without using loops or conditionals.

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