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How Can I Efficiently Extract Integer Values from a Byte Buffer in Go?

Linda Hamilton
Release: 2024-11-27 19:32:11
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How Can I Efficiently Extract Integer Values from a Byte Buffer in Go?

Extracting Integer Values from Byte Buffer in Golang

You require a technique to extract various fields from a byte buffer in Go. While your current approach using bytes.Buffer and explicit offsets effectively achieves this, there are potential improvements to consider.

Alternative with Byte Skipping

To eliminate the creation of multiple buffers, you can use the bytes.Buffer.Next() method:

func readSB(buf []byte) {
    p := bytes.NewBuffer(buf)

    binary.Read(p, binary.LittleEndian, &fs.sb.inodeCount)
    binary.Read(p, binary.LittleEndian, &fs.sb.blockCount)
    p.Next(12)
    binary.Read(p, binary.LittleEndian, &fs.sb.firstDataBlock)
    binary.Read(p, binary.LittleEndian, &fs.sb.blockSize)
    p.Next(4)
    binary.Read(p, binary.LittleEndian, &fs.sb.blockPerGroup)
    p.Next(4)
    binary.Read(p, binary.LittleEndian, &fs.sb.inodePerBlock)
}
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Structure-Based Reading

An alternative approach is to create a header structure and use binary.Read directly:

type Head struct {
    InodeCount      uint32  //  0:4
    BlockCount      uint32  //  4:8
    // Skip fields
    FirstBlock      uint32  // 20:24
    BlockSize       uint32  // 24:28
    // Skip fields
    BlocksPerGroup  uint32  // 32:36
    // Skip fields
    InodesPerBlock  uint32  // 40:44
}

func readSB(buf []byte) {
    var header Head
    if err := binary.Read(bytes.NewReader(buf), binary.LittleEndian, &header); err != nil {
        log.Fatal(err)
    }

    // Access data using header fields
}
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