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How Can I Efficiently Convert a Go Slice of `float32` to `float64`?

Susan Sarandon
Release: 2024-11-29 04:34:19
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How Can I Efficiently Convert a Go Slice of `float32` to `float64`?

Efficiently Converting Numeric Slices in Go

Working with numeric slices in Go often involves the need to convert them between different numeric types. This question addresses the issue of efficiently converting a slice of type float32 to float64.

Iterative Approach

Iterating through individual elements and explicitly converting their types is a common approach. While simple, it can be inefficient for large slices. However, in Go, this iterative technique is typically the most efficient due to the language's low-level nature.

Optimization Tricks

To optimize the iterative approach, consider using the built-in range loop instead of the for loop with indexing. range avoids the overhead of bounds checking, resulting in a faster conversion.

func convertTo64(ar []float32) []float64 {
   newar := make([]float64, len(ar))
   var v float32
   var i int
   for i, v = range ar {
      newar[i] = float64(v)
   }
   return newar
}
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Example Usage

The following code demonstrates the usage of the optimized conversion method:

slice32 := make([]float32, 1000)
slice64 := convertTo64(slice32)
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Incorrect Assumptions

While this question suggests that there may be built-in functions for slice conversion, this is not the case. All predefined functions for such operations ultimately rely on iteration behind the scenes.

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