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Why Doesn\'t `cout` Print `unsigned char` Values Correctly?

Barbara Streisand
Release: 2024-11-29 11:53:10
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Why Doesn't `cout` Print `unsigned char` Values Correctly?

Why is cout Not Printing unsigned char Correctly?

In the provided code:

#include <iostream>
#include <stdio.h>

using namespace std;

int main() {
    unsigned char a = 1;
    printf("%d", a);
    cout << a;
}
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The output includes a value that appears as garbage when printed using cout. This occurs because the ASCII character corresponding to the value of a (1) is non-printable. To verify this, use std::isprint as follows:

std::cout << std::isprint(a) << std::endl;
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The result will be 0 (false), indicating that the character is non-printable.

To resolve this issue and have cout print "1", cast a to an unsigned integer:

cout << static_cast<unsigned>(a) << std::endl;
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