How to Correctly Print the Address of a Struct in Go?

Understanding Struct Address Printing in Go

In Go, understanding the concept of printing the address of a struct variable is crucial. Let's delve into a specific query and its solution.

Query:

A user encountering Go for the first time wants to print the address of a struct variable, r. Despite using the expected & operator, the output shows {15 6} instead of the expected address.

Code Snippet:

type Rect struct {
  width int
  name int
}

func main() {
  r := Rect{4, 6}
  p := &r
  p.width = 15

  fmt.Println("-----", &p, r, p, &r)
}

Analysis:

By default, fmt.Println() uses the %v format which treats structs specially by printing their fields. To print the address directly, a specific format string is required.

Solution:

To print the address of r, the %p verb must be used with a format string. This verb specifically indicates the printing of a pointer value.

fmt.Printf("%p\n", &r)

This will correctly output the address of r, such as 0x414020.

Additionally, the address can be stored in a variable using the following syntax:

addr := &r

Now, addr will hold the pointer to r.

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