How to Print the Value, Not the Pointer, of Nested Structs in Go?

Printing Struct Values with Pointers in Go

In Go, when printing a struct value that contains pointers, the pointer address is typically printed instead of the actual value. This can be problematic when trying to inspect the contents of a nested struct.

How to Print the B Struct Value Instead of the Pointer

To solve this issue, you have two options:

1. Implement the Stringer Interface:

   Implement the String() method for the A and B structs. This method returns a formatted string representation of the struct. In the implementation, print the desired values instead of the pointers.

   package main
   
   import "fmt"
   
   type A struct {
       a int32
       B *B
   }
   
   type B struct {
       b int32
   }
   
   func (aa *A) String() string {
       return fmt.Sprintf("A{a:%d, B:%v}", aa.a, *aa.B)
   }
   
   func (bb *B) String() string {
       return fmt.Sprintf("B{b:%d}", bb.b)
   }
   
   func main() {
       a := &A{a: 1, B: &B{b: 2}}
       fmt.Println(a)
   }

2. Print Values Manually:

   Access the actual values of the B struct manually and print them directly.

   package main
   
   import "fmt"
   
   type A struct {
       a int32
       B *B
   }
   
   type B struct {
       b int32
   }
   
   func main() {
       a := &A{a: 1, B: &B{b: 2}}
       fmt.Printf("A{a:%d, B:{b:%d}}\n", a.a, a.B.b)
   }

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