Home > Database > Mysql Tutorial > Why Am I Getting \'Unread Result Found\' Errors with Python\'s MySQL Connector and How Can I Fix Them?

Why Am I Getting \'Unread Result Found\' Errors with Python\'s MySQL Connector and How Can I Fix Them?

DDD
Release: 2024-11-30 21:53:15
Original
208 people have browsed it

Why Am I Getting

Python MySQL Connector: Unread Result Found When Using Fetchone

In Python, encountering "Unread result found" errors while utilizing the MySQL connector often stems from using the fetchone() function without properly consuming all results. This error occurs when executing subsequent queries without first fetching and consuming any existing results from previous queries.

To resolve this issue, ensure that all results from executed queries are fetched and consumed before moving on to subsequent queries. One approach is to use the cursor.fetchall() method to retrieve all results and clear the buffer. This can be achieved by adding try/except blocks to capture and handle any InterfaceErrors.

However, in this specific scenario, the issue lies in the lack of a buffered cursor. By default, cursors are created without buffering. Enabling buffering ensures that all results from a query are pre-fetched and reside within the client memory. To enable buffering, initiate the cursor with the buffered=True parameter:

cursor = cnx.cursor(buffered=True)
Copy after login

With buffered cursors, fetchone() will return a single row from the pre-fetched result set, eliminating the error caused by unread results. It's important to note that buffered cursors may consume more memory, especially when working with large result sets. Consider using unbuffered cursors for improved performance in such cases. Remember to manually fetch and consume all results to prevent the "Unread result found" error.

The above is the detailed content of Why Am I Getting \'Unread Result Found\' Errors with Python\'s MySQL Connector and How Can I Fix Them?. For more information, please follow other related articles on the PHP Chinese website!

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template