


Can a Single Function Replace Both the Copy Constructor and Copy Assignment Operator?
Can a Single Function Handle Both the Copy Constructor and Copy Assignment Operator?
In programming, the copy constructor and copy assignment operator are often used together to define object copy behavior. Both operations share similar code and parameters, differing only in their return types. This raises the question: is it possible to create a common function that handles both scenarios?
Answer:
Yes, there are two main approaches to achieve this:
1. Explicitly Calling the Assignment Operator from the Copy Constructor:
MyClass(const MyClass& other) { operator=(other); }
However, this approach has drawbacks. It places additional responsibility on the assignment operator to handle the old state and self-assignment issues, which can be challenging. Additionally, this method requires all members to be initialized first, which can be redundant and potentially expensive.
2. Copy and Swap Idiom:
This approach implements the copy assignment operator using the copy constructor and a swap method:
MyClass& operator=(const MyClass& other) { MyClass tmp(other); swap(tmp); return *this; }
The swap method is responsible for exchanging the internals of the two objects without cleaning up or allocating new resources. This method provides several advantages:
- Self-assignment Safe: The copy and swap idiom is automatically safe against self-assignment.
- Exception Safe: It is also strongly exception safe if the swap operation is no-throw.
- Simplified Implementation: Implementing the swap method is typically straightforward, avoiding the complexities of a handwritten assignment operator.
Caution: It's important to ensure that the swap method performs a true swap, rather than relying on the default std::swap, which may use the copy constructor and assignment operator itself.
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