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How to Create a JSON Object in PHP with an 'item' Key Enclosing the Data?

Patricia Arquette
Release: 2024-12-02 08:51:09
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How to Create a JSON Object in PHP with an

Creating JSON Objects in PHP

When working with complex data structures, it is often necessary to create JSON objects from PHP arrays. The following question explores this topic:

Question:

How can I encapsulate a created JSON code in the "item": { JSON CODE HERE } format?

Given Array:

$post_data = array('item_type_id' => $item_type,
    'string_key' => $string_key,
    'string_value' => $string_value,
    'string_extra' => $string_extra,
    'is_public' => $public,
    'is_public_for_contacts' => $public_contacts);
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Expected Output:

{
    "item": {
        "is_public_for_contacts": false,
        "string_extra": "100000583627394",
        "string_value": "value",
        "string_key": "key",
        "is_public": true,
        "item_type_id": 4,
        "numeric_extra": 0
    }
}
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Answer:

To encapsulate the JSON code in the "item": { } format, it is necessary to tweak the JSON encoding process. Here's the solution:

$post_data = json_encode(array('item' => $post_data), JSON_FORCE_OBJECT);
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By passing the JSON_FORCE_OBJECT constant as the second argument to json_encode(), you instruct the function to encode the data as an object, ensuring that the output will be enclosed within "{}" brackets.

Remember that "{}", according to the JSON specification, represents an object while "[]" represents an array.

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