Day - Looping and Puzzle program

1.Collatz sequence
Write a program that prints the Collatz sequence for a given number until it reaches 1.

Rule:

    If the number is even: n=n/2
    If the number is odd: n=3n+1.

def even_odd(no):

    while no>0:
        num=no%10
        if num%2==0:
            even=num/2
            print(even)
        else:
            odd=3*num+1
            print(odd)

        no=no//10


no=int(input("Enter the number:"))
even_odd(no)

Enter the number:12345
16
2.0
10
1.0
4

*2.Find all digits in a number are equal
*

no = int(input("Enter no. "))   
equal = no%10
while no>0:
    rem = no%10 
    if rem == equal:
        equal=rem
    else:
        print("All Numbers are not equal")
        break
    no//=10 
else:
    print("All numbers are equal")

Enter no. 1234
All Numbers are not equal
Enter no. 4444
All numbers are equal

Puzzle Program:

1.In 4 hours, the horse covers a total of 4 feet, as it runs 1 foot in the first hour, 2 feet in the second hour, 3 feet in the third hour, and 4 feet in the fourth hour.
If the horse takes 12 steps to cover 1 foot, and it runs a total of 10 feet in 4 hours, the total number of steps the horse takes is:

10 feet×12 steps per foot=120 steps.

In 4 hours, the horse covers 10 feet by taking 120 steps.

total = 0
steps = 12
ft = 1
while ft<=4:
    total = total + steps*ft 
    ft+=1
print(total)

120

2.Each day, the frog climbs 1 foot but slides back 0.5 foot at the end of the day.
Thus, the gain per day is 1−0.5=0.5foot.
However, on the day the frog reaches or exceeds 30 feet, it will not slide back.
Find out how many days frog takes to reach the top.

height = 30
up = 1
down = 0.5
total = 0
days = 0
while total<height:
    total = total + up - down 
    days+=1

print(days)

60

3.If a clock is delayed by 5 minutes initially and further delays by 5 minutes every hour.
How many minutes it will be delay from 8 am to 1pm.

morning = 8
afternoon = 13
difference = 5
late = 0
while difference>0:
    late = late + 5
    difference-=1
print(late)

25    

4.Convert railway time to normal time and normal time to railway time.
Railway Time to normal time:
15:09 - 3:09
Normal Time to Railway Time:
3:09 - 15:09

time=float(input("Enter the time:"))
if time<=12:
    calculate_time=time+12
    print("time:",calculate_time)

else:
    calculate_time=12-time
    print("time:",round(-calculate_time,2))

Enter the time:15.09
time: 3.09
Enter the time:3.09
time: 15.09

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