Task:1
#Print Numbers #Write a program to print numbers from 1 to 10 using a while loop. def print_numbers(num): no=1 while no<=num: print(no,end=' ') no+=1 print_numbers(10)
Output:
1 2 3 4 5 6 7 8 9 10
Task:2
#Sum of N Numbers #Write a program to calculate the sum of the first NN natural numbers using a while loop. def nat_num(N): sum = 0 natural_no = 1 while natural_no <= N: sum += natural_no natural_no += 1 return sum N = int(input("Enter the no: ")) print(nat_num(N))
Output:
Enter the no: 10 Sum of 10 natural numbers are 55
Task:3
#Find even numbers between 1 to 50 def even_number(num): no=2 while no<=num: print(no, end=" ") no+=2 num=int(input("Enter the number: ")) even_number(num)
Output:
2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 42 44 46 48 50
Task:4
#Find odd numbers between 1 and NN def odd_number(num): no=1 while no<=num: print(no, end=" ") no+=2 num=int(input("Enter the number:")) odd_number(num)
Output:
Enter the number:15 1 3 5 7 9 11 13 15
Task:5
#Multiplication table of number NN #NN-2 no=1 while no<=10: print(f'{no}*2={no*2}') no+=1
Output:
1*2=2 2*2=4 3*2=6 4*2=8 5*2=10 6*2=12 7*2=14 8*2=16 9*2=18 10*2=20
Factorial:
Write a program to calculate the factorial of a given number using a while loop.
Case-1
no = 1 factorial = 1 factorial = factorial * no #1 no = no+1 #2 factorial = factorial * no #2 no = no+1 #3 factorial = factorial * no #6 no = no+1 #4 factorial = factorial * no #24 no = no+1 #5 factorial = factorial * no #120 print(factorial)
Case-2
def find_factorial(num): no=1 factorial=1 while no<=num: factorial=factorial*no no+=1 return factorial num=int(input("Enter the number:")) print(find_factorial(num))
For scenarios output will be same
Output:
Enter the number:5 120
Sum of digits:
Find the sum of the digits of a given number (e.g., 123 → 1 2 3=61 2 3=6).
def sum_of_digits(num): sum=0 while num>0: sum=sum+num%10 num=num//10 return sum num=int(input("Enter the number:")) print(sum_of_digits(num))
Output:
Enter the number:123 6
Count Digits
To count the number of digits in a given number (e.g., 12345 → 5 digits).
def count_of_digits(no): count=0 while no>0: no=no//10 count+=1 return count no=int(input("Enter the number:")) print(count_of_digits(no))
Output:
Enter the number:12345 5
Reverse numbers
To reverse a number
def reverse_no(num): reverse = 0 while num>0: reverse = (reverse*10) + num%10 num = num//10 return reverse print(reverse_no(1234))
Output:
Enter the number:12345 54321
Check Palindrome
check if a given number is a palindrome (e.g., 121 → palindrome, 123 → not a palindrome).
def palindrome(num): count=0 while num>0: count=count*10+num%10 num=num//10 return count num=int(input("Enter the number:")) result=palindrome(num) if result==num: print("Palindrome") else: print("Not palindrome")
Output:
Enter the number:121 Palindrome Enter the number:123 Not palindrome
Find power
def find_power(base,power): result=1 while power>=1: result=result*base power-=1 return result base=int(input("Enter the base number:")) power=int(input("Enter the power number:")) result=find_power(base,power) print(result)
Output:
Enter the base number:5 Enter the power number:2 25
Armstrong Number
Example:
def count_of_digits(num): count=0 while num>0: num=num//10 count+=1 return count def find_power(base,power): result=1 while power>=1: result=result*base power-=1 return result def find_armstrong(num): armstrong=0 while num>0: rem=num%10 result= find_power(rem,count) armstrong=armstrong+result num=num//10 return armstrong num=int(input("Enter the number:")) count=count_of_digits(num) armstrong_result=find_armstrong(num) if armstrong_result==num: print("Armstrong") else: print("Not armstrong")
Output:
Enter the number:135 Not armstrong Enter the number:153 Armstrong
The above is the detailed content of Python Day - Looping-Examples and Tasks. For more information, please follow other related articles on the PHP Chinese website!