Home > Java > javaTutorial > Why Does My Selenium XPath Expression Result in a 'Not a Valid XPath Expression' Error?

Why Does My Selenium XPath Expression Result in a 'Not a Valid XPath Expression' Error?

DDD
Release: 2024-12-04 08:22:10
Original
257 people have browsed it

Why Does My Selenium XPath Expression Result in a

XPath Expression Evaluation Error: "Not a Valid XPath Expression"

When attempting to locate and select an element using Selenium in Java, you may encounter the following error:

The string '//*[@id='app']/article/div[2]/section/div[1]/div[5]/div/section[2]/div[2]/div[1]/' is not a valid XPath expression.
Copy after login

This error indicates that the provided XPath expression is not syntactically correct. There are two main issues with the given expression:

  1. Unmatched Single Quotes: You are using single quotes ('') to enclose the XPath expression, but you cannot use single quotes within the attribute values.
  2. Trailing Slash: An XPath expression should not end with a slash (/).

To resolve this error, you can modify the XPath expression in one of the following ways:

  • Remove Single Quotes: Use double quotes (") to enclose the XPath expression instead of single quotes.
  • Eliminate Trailing Slash: Remove the trailing slash from the end of the expression.

Your corrected XPath expression should be as follows:

//*[@id="app"]/article/div[2]/section/div[1]/div[5]/div/section[2]/div[2]/div[1]
Copy after login

Alternatively, you can also use double quotes (") to enclose the expression:

"//*[@id='app']/article/div[2]/section/div[1]/div[5]/div/section[2]/div[2]/div[1]"
Copy after login

By making these corrections, you should be able to successfully locate and select the desired element on the webpage.

The above is the detailed content of Why Does My Selenium XPath Expression Result in a 'Not a Valid XPath Expression' Error?. For more information, please follow other related articles on the PHP Chinese website!

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template