Why does constexpr exclude undefined behavior?
The C standard requires that constexpr expressions must not involve undefined behaviors. This allows compilers to prevent errors or unexpected results that could arise from evaluating expressions with undefined behaviors during compilation.
Advantages of this Exclusion
By excluding undefined behaviors, the compiler can:
Specific Benefits
The exclusion of undefined behaviors in constexpr expressions is particularly useful for the following scenarios:
Supporting Evidence
The following code examples demonstrate the exclusion of undefined behaviors in constexpr expressions:
// Integer overflow (undefined behavior) not allowed in constexpr constexpr int x = std::numeric_limits<int>::max() + 1; // Error
// Pointer arithmetic (undefined behavior) not allowed in constexpr constexpr int *ptr = &x[20]; // Error
// Shift operation (undefined behavior) not allowed in constexpr constexpr int y = 1 << 33; // Error (assuming 32-bit int)
However, it's important to note that different compilers may handle certain types of undefined behaviors differently, particularly for shift operations.
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