Why Does Explicit Specialization of Class Members Fail Outside a Namespace in C ?

Explicit Specialization Outside Namespace Scope: An Error in Non-Standard G

C template programming involves the explicit specialization of class members for efficient code generation. However, the placement of explicit specializations is crucial, as demonstrated by the following code snippet:

template<typename T>
class CConstraint
{
    // ...

    template <typename TL>
    void Verify(int position, int constraints[])
    {
    }

    template <>
    void Verify<int>(int, int[])
    {
    }
};

When compiled with g , this code results in the error:

Explicit specialization in non-namespace scope 'class CConstraint'

To understand this error, we need to examine the C standard, which dictates that explicit specializations must be declared within the namespace of which the template is a member. In the above example, CConstraint is not declared inside any namespace, and thus the explicit specialization of Verify is invalid.

VC compilers, however, are non-compliant in this case, allowing explicit specializations outside namespace scope. This behavior is non-standard and should not be relied upon.

Solution:

To resolve this issue and ensure compliance with the C standard, explicit specializations must be declared within the same namespace as the template they specialize. Here is a corrected version of the code:

namespace MyNamespace
{
    template<typename T>
    class CConstraint
    {
        // ...

        template <typename TL>
        void Verify(int position, int constraints[])
        {
        }

        template <>
        void Verify<int>(int, int[])
        {
        }
    };
}

By encapsulating CConstraint within the MyNamespace namespace, we ensure that its explicit specializations are also declared within that namespace, resolving the compilation error.

Additionally, since C 03 prohibits specializing member functions without explicitly specializing the containing class, we could also consider using a free function approach, as suggested in the provided answer:

namespace detail {
    template <typename TL> void Verify(int, int[]) {}
    template <>            void Verify<int>(int, int[]) {}
}

template<typename T> class CConstraint {
    // ...
    template <typename TL> void Verify(int position, int constraints[]) {
        detail::Verify<TL>(position, constraints);
    }
};

The above is the detailed content of Why Does Explicit Specialization of Class Members Fail Outside a Namespace in C ?. For more information, please follow other related articles on the PHP Chinese website!