Python provides a convenient way to retrieve the filename from a path, irrespective of the operating system or path format.
The os.path.basename(path) function is designed specifically for extracting the filename from a path. It eliminates any leading directories or drive letters, returning only the filename itself.
For instance, consider the following paths:
a/b/c/ a/b/c \a\b\c \a\b\c\ a\b\c a/b/../../a/b/c/ a/b/../../a/b/c
For each of these paths, os.path.basename would return the filename "c".
To use os.path.basename(), simply import the os module and pass the path to the function as shown below:
import os your_path = 'a/b/c/' result = os.path.basename(your_path) print(result) # Output: 'c'
It's important to note that when using os.path.basename() on a POSIX system to extract the base name from a Windows-style path (e.g., "C:\my\file.txt"), the entire path will be returned. To rectify this issue, consider using alternative methods or handling the paths differently based on the operating system.
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