How to Generate XPaths for All Nodes in an XML Document Using Java?
Dec 07, 2024 am 08:05 AMGenerate/Get Xpath from XML in Java
Interested in advice rather than actual implementation. Looking for a Java approach to traverse an XML document, check nodes for attribute existence, and generate Xpaths.
Goal
To generate Xpaths for all nodes in the following XML document:
<root> <elemA>one</elemA> <elemA attribute1='first' attribute2='second'>two</elemA> <elemB>three</elemB> <elemA>four</elemA> <elemC> <elemB>five</elemB> </elemC> </root>
Expected Result:
//root[1]/elemA[1]='one' //root[1]/elemA[2]='two' //root[1]/elemA[2][@attribute1='first'] //root[1]/elemA[2][@attribute2='second'] //root[1]/elemB[1]='three' //root[1]/elemA[3]='four' //root[1]/elemC[1]/elemB[1]='five'
Update
This solution uses an XSLT transformation to achieve the desired result:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="text"/> <xsl:strip-space elements="*"/> <xsl:variable name="vApos"'>'</xsl:variable> <xsl:template match="*[@* or not(*)] "> <xsl:if test="not(*)"> <xsl:apply-templates select="ancestor-or-self::*" mode="path"/> <xsl:value-of select="concat('=',$vApos,.,$vApos)"/> <xsl:text>&#xA;</xsl:text> </xsl:if> <xsl:apply-templates select="@*|*"/> </xsl:template> <xsl:template match="*" mode="path"> <xsl:value-of select="concat('/',name())"/> <xsl:variable name="vnumPrecSiblings" select="count(preceding-sibling::*[name()=name(current())])"/> <xsl:if test="$vnumPrecSiblings"> <xsl:value-of select="concat('[', $vnumPrecSiblings +1, ']')"/> </xsl:if> </xsl:template> <xsl:template match="@*"> <xsl:apply-templates select="../ancestor-or-self::*" mode="path"/> <xsl:value-of select="concat('[@',name(), '=',$vApos,.,$vApos,']')"/> <xsl:text>&#xA;</xsl:text> </xsl:template> </xsl:stylesheet>
When applied to the provided XML document, it produces the expected Xpaths.
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