Getting a Path to Resources in a Java JAR File
Question:
Retrieving a path to a resource (e.g., a config file) within a JAR file has proven unsuccessful. Attempts to use the class loader with getResourceAsStream() and getFile() yield exceptions or a path referencing the JAR file itself. Is it possible to obtain a valid file path?
Answer:
Retrieving a file path to a resource within a JAR file is inherently challenging due to potential limitations in the class loader. JAR files often contain resources that are not physically present as individual files on the file system.
Accessing a resource's content is possible through classLoader.getResourceAsStream(), which returns an input stream for reading the resource's contents. However, attempting to convert this to a file with getFile() may result in an exception as the resource may not have a corresponding file path.
If a file handle is absolutely essential, it is recommended to create a temporary file, copy the resource's contents into it, and then use the temporary file's path. This alternative approach ensures availability of a valid file path.
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