The map() method creates a new array by applying a provided function (callbackFn) to each element of the original array. It’s perfect for transforming data without modifying the original array.
array.map(callbackFn, thisArg)
const numbers = [1, 4, 9]; const roots = numbers.map((num) => Math.sqrt(num)); console.log(roots); // [1, 2, 3]
const kvArray = [ { key: 1, value: 10 }, { key: 2, value: 20 }, ]; const reformatted = kvArray.map(({ key, value }) => ({ [key]: value })); console.log(reformatted); // [{ 1: 10 }, { 2: 20 }]
// Common mistake: console.log(["1", "2", "3"].map(parseInt)); // [1, NaN, NaN] // Correct approach: console.log(["1", "2", "3"].map((str) => parseInt(str, 10))); // [1, 2, 3] // Alternative: console.log(["1", "2", "3"].map(Number)); // [1, 2, 3]
Returning nothing from the callback leads to undefined in the new array:
const numbers = [1, 2, 3, 4]; const result = numbers.map((num, index) => (index < 3 ? num : undefined)); console.log(result); // [1, 2, 3, undefined]
Use filter() or flatMap() to remove undesired elements.
Avoid using map() for operations with side effects, like updating variables:
const cart = [5, 15, 25]; let total = 0; // Avoid this: const withTax = cart.map((cost) => { total += cost; return cost * 1.2; }); // Instead, use separate methods: const total = cart.reduce((sum, cost) => sum + cost, 0); const withTax = cart.map((cost) => cost * 1.2);
The third argument (array) allows accessing neighbors during transformations:
const numbers = [3, -1, 1, 4]; const averaged = numbers.map((num, idx, arr) => { const prev = arr[idx - 1] || 0; const next = arr[idx + 1] || 0; return (prev + num + next) / 3; }); console.log(averaged);
const elems = document.querySelectorAll("option:checked"); const values = Array.from(elems).map(({ value }) => value);
const products = [{ name: "phone" }]; const updated = products.map((p) => ({ ...p, price: 100 }));
Use map() to simplify your code when transforming arrays efficiently!
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