Home > Backend Development > C++ > Why Can't I Use Floating-Point Numbers as C Template Parameters?

Why Can't I Use Floating-Point Numbers as C Template Parameters?

Patricia Arquette
Release: 2024-12-10 01:16:09
Original
1078 people have browsed it

Why Can't I Use Floating-Point Numbers as C   Template Parameters?

Why Float Values Are Not Allowed as Template Parameters

In C , attempting to use a float value as a template parameter, as in the following code, results in the following error:

GenericClass<float, 4.6f> gcFloat;
error: `float' is not a valid type for a template constant parameter
Copy after login

Standard Prohibition

According to the C 11 standard, non-type template arguments must be one of the following:

  • Converted constant expressions of integral or enumeration types
  • Non-type template parameter names
  • Expressions designating addresses of static objects or functions
  • Null pointers
  • Null member pointers
  • Pointers to members

Floating point values, however, do not fit into any of these categories.

Reasoning

The primary reason for this restriction is the imprecise nature of floating point computations. Floating point calculations cannot be represented exactly, which could lead to unexpected behavior when using them as template arguments. For example, the following code may not behave as intended due to potential rounding differences:

func<1/3.f>();
func<2/6.f>();
Copy after login

Alternative Solutions

To represent floating point values as template arguments, consider using advanced constant-expressions (constexpr) in C 11 to calculate the numerator and denominator of the floating value at compile time. These can then be passed as separate integer arguments. However, it is crucial to define a threshold to ensure that floating point values close to each other yield the same numerator/denominator ratio.

The above is the detailed content of Why Can't I Use Floating-Point Numbers as C Template Parameters?. For more information, please follow other related articles on the PHP Chinese website!

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Latest Articles by Author
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template