Home Backend Development Golang Is Go\'s encoding/gob Deterministic, and If Not, Under What Conditions?

Is Go\'s encoding/gob Deterministic, and If Not, Under What Conditions?

Dec 11, 2024 pm 02:24 PM

Is Go's encoding/gob Deterministic, and If Not, Under What Conditions?

Determinism in Encoding/gob

The encoding/gob package in Go enables object serialization to a stream of bytes. This package is often used for data exchange across processes or network communication. A fundamental question arises: is the output of encoding/gob deterministic?

Current implementations of encoding/gob, as of this discussion, produce deterministic results. However, this determinism is not absolute.

Non-Determinism Due to Interface and Map Iteration

The original question assumes no usage of interfaces or maps. However, when encoding/gob encounters maps, non-determinism can arise. This is due to the random order of iteration for maps, resulting in varying serialization order of their elements.

Determinism with Type References

Encoding/gob uses type references to minimize the size of the encoded stream. When encountering a new type, its specification is sent. For subsequent values of the same type, only a reference to the previous type specification is included. This results in varying output depending on the first occurrence of a particular type.

Consistency with Multiple Encoders

While encoding/gob's output may vary among different Go versions, it remains consistent when using the same gob.Encoder for a particular set of values. This ensures that data can be decoded correctly as long as the same version of Go is used.

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