What Determines the Execution Order of Initializers in Java?

Initializer Execution Order in Java

The given code snippet raises a question regarding the order in which fields and constructors are initialized in Java. Contrary to the expectation that constructors precede field initialization, the output of the program - "YXZY" - suggests otherwise.

To clarify this behavior, let's delve into the actual initialization order in Java:

1. Static Variable Initializers and Blocks:

   • Any static variable initializers and static initialization blocks are executed first, ensuring that all static members are initialized before any instances of the class are created.

2. Super() Call:

   • The call to the super() constructor, whether explicit or implicit, is the next step. This call initializes the parent class's fields and constructor.

3. Instance Variable Initializers and Blocks:

   • Next, the instance variable initializers and instance initialization blocks are executed, initializing the instance members in the order they appear in the code.

4. Constructor Body:

   • Finally, the remaining body of the constructor is executed, completing the initialization process.

The above is the detailed content of What Determines the Execution Order of Initializers in Java?. For more information, please follow other related articles on the PHP Chinese website!