How Can Go's `math/big` Package Handle Hexadecimal Strings Larger Than int64?

Parsing Long Hexadecimal Strings into Decimal Notation Using math/big

In this scenario, the inability to use ParseUint() is encountered due to its support limitations for int64. To overcome this obstacle, the math/big package provides a solution for working with numbers beyond the confines of 64 bits.

This broadens the scope of precision in handling large hexadecimal numbers. To illustrate its application, the following example presents an alternative approach using math/big:

package main

import (
    "fmt"
    "math/big"
)

func main() {
    s := "0x00000000000000000000000000000000000000000000d3c21bcecceda1000000"
    i := new(big.Int)

    // Conversion to a big.Int from a hexadecimal string
    i.SetString(s, 16)

    // Print the resulting big.Int
    fmt.Println(i)
}

The output of this program will be the converted and expanded integer value.

Other Math/Big Interface Support

In addition to its core functionality, math/big also offers support for the encoding.TextMarshaler and fmt.Scanner interfaces. This enables seamless handling of large integers for custom data types and scanning.

For instance, consider the following code:

package main

import (
    "fmt"
    "math/big"
)

func main() {
    i := new(big.Int)

    // Parsing from a string
    fmt.Sscan("0x000000d3c21bcecceda1000000", i)

    // Alternative parsing using fmt.Sscanf
    fmt.Sscanf("0x000000d3c21bcecceda1000000", "0x%x", i)
}

In this example, the math/big package's support for other interfaces simplifies the process of parsing large hexadecimal strings into decimal notation.

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