Why Am I Getting 'Call to a member function execute() on a non-object' with mysqli Prepared Statements?

Understanding Mysqli Prepared Statements

Preparing statements is a crucial practice for preventing SQL injection vulnerabilities. However, a common error encountered when using mysqli prepared statements is receiving the error "Call to a member function execute() on a non-object."

To resolve this issue and effectively use mysqli prepared statements, you'll need to understand the following:

1. Parameter Binding: After preparing a statement, you must bind parameters to the placeholders (?) in the SQL query. This is done using the bind_param() method.
2. Execution: Once the parameters are bound, you can execute the prepared statement using the execute() method.

Here's an example to illustrate the complete process:

<?php

// Connect to MySQL
$mysqli = new mysqli("localhost", "root", "root", "test");

// Prepare statement
$stmt = $mysqli->prepare("INSERT INTO users (name, age) VALUES (?, ?)");

// Bind parameters
$name = 'one';
$age = 1;
$stmt->bind_param('si', $name, $age);

// Execute statement
$stmt->execute();

// Insert another row with different values
$name = 'two';
$age = 2;
$stmt->bind_param('si', $name, $age);
$stmt->execute();

?>

Using mysqli for prepared statements is highly recommended as it's the recommended way to protect against SQL injection in PHP. The example above covers not only connection, insertion, and selection, but also provides error handling.

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