Home Backend Development Golang How to Efficiently Compare Binary Trees in Go: Solving the Go Tour Exercise #7?

How to Efficiently Compare Binary Trees in Go: Solving the Go Tour Exercise #7?

Dec 16, 2024 am 10:32 AM

How to Efficiently Compare Binary Trees in Go: Solving the Go Tour Exercise #7?

Go Tour Exercise #7: Binary Trees Equivalence

The Go Tour exercise "Binary Trees" challenges you to determine if two binary trees contain the same values. The exercise focuses on writing a recursive Walk function that traverses the trees and sends their values to a channel.

In the code you provided, you encounter an issue determining when the trees have been fully traversed. While closing the channel could seem intuitive, it would terminate the traversal prematurely due to the recursive nature of the Walk function.

One solution to this problem is to utilize closures. By leveraging a closure-based version of the Walk function, you can defer closing the channel until all values have been sent. The modified code below demonstrates this technique:

func Walk(t *tree.Tree, ch chan int) {
    defer close(ch) // Automatically closes the channel when this function returns

    var walk func(t *tree.Tree)
    walk = func(t *tree.Tree) {
        if t == nil {
            return
        }
        walk(t.Left)
        ch <- t.Value
        walk(t.Right)
    }
    walk(t)
}
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With this modification, the Walk function automatically closes the channel once all values have been sent, signaling the completion of the traversal. This allows the Same function to effectively compare the values from both trees by receiving them from the channels and ensuring they are identical.

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