Home > Java > javaTutorial > How to Efficiently Create Comma-Delimited Strings in Java?

How to Efficiently Create Comma-Delimited Strings in Java?

Linda Hamilton
Release: 2024-12-17 01:42:25
Original
668 people have browsed it

How to Efficiently Create Comma-Delimited Strings in Java?

 Building Comma-Delimited Strings in Java

In Java, assembling a list of values into a delimited string is a common requirement. While basic approaches involve iterative concatenation, cleaner alternatives exist.

Pre-Java 8:

Leverage Apache's commons lang library, which provides a StringUtils.join() method analogous to Ruby's join.

Java 8 onwards:

StringJoiner:

  • Create a StringJoiner instance with the desired delimiter.
  • Add elements to the joiner using the add() method.
  • Convert the joiner to a string using toString().

String.join(delimiter, array):

  • Use String.join() with the delimiter and an array of elements as arguments.
  • This method concatenates the elements into a string separated by the delimiter.

String.join(delimiter, iterable):

  • Similar to the previous method, but accepts an iterable collection of elements instead of an array.

Example:

// Using StringJoiner
List<String> list = new ArrayList<>();
list.add("element1");
list.add("element2");
StringJoiner joiner = new StringJoiner(",");
joiner.addAll(list);
String delimitedString = joiner.toString();

// Using String.join(array)
String[] elements = new String[] {"element1", "element2"};
String delimitedString = String.join(",", elements);

// Using String.join(iterable)
List<String> list2 = new ArrayList<>();
list2.add("element1");
list2.add("element2");
String delimitedString = String.join(",", list2);
Copy after login

These methods provide efficient and elegant solutions for creating delimited strings in Java, eliminating the need for multiple string creations and concatenation.

The above is the detailed content of How to Efficiently Create Comma-Delimited Strings in Java?. For more information, please follow other related articles on the PHP Chinese website!

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Latest Articles by Author
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template