Home Backend Development Golang How Does Slicing Affect Go Slice Capacity?

How Does Slicing Affect Go Slice Capacity?

Dec 17, 2024 am 08:22 AM

How Does Slicing Affect Go Slice Capacity?

Understanding Slice Capacity Reduction

Go slices are efficient data structures that use an underlying array for storage. They are represented by a combination of length and capacity, where capacity defines the maximum number of elements that the slice can hold.

Slice Capacity Changes

Manipulating a slice can sometimes affect its capacity:

  • s = s[:0] and s = s[:4] leave the slice capacity unchanged because they do not modify the underlying pointer to the array.
  • s = s[2:] decreases the slice capacity because it changes the pointer to the new slice by dropping the first two elements.

Example

Consider the following Go program:

package main

import "fmt"

func main() {
    s := []int{2, 3, 5, 7, 11, 13}
    printSlice(s)

    s = s[:0]
    printSlice(s)

    s = s[:4]
    printSlice(s)

    s = s[2:]
    printSlice(s)
}

func printSlice(s []int) {
    fmt.Printf("len=%d cap=%d %v\n", len(s), cap(s), s)
}
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Running this program outputs:

len=6 cap=6 [2 3 5 7 11 13]
len=0 cap=6 []
len=4 cap=6 [2 3 5 7]
len=2 cap=4 [5 7]
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Explanation

Initially, the slice has a length of 6 and a capacity of 6. Changing its length to 0 does not modify the pointer, so the capacity remains unchanged. Extending the length to 4 also keeps the capacity the same. However, slicing the slice from the 2nd element onwards (s = s[2:]) changes the pointer, resulting in a new slice with a length of 2 and a capacity of 4.

Data Recovery

s = s[2:] removes the first two elements from the slice. If you need to recover them, you will need to create a new slice that includes them before performing the s = s[2:] operation.

Memory Representation of Slices

Understanding the memory representation of slices is crucial for comprehending why the capacity of s = s[2:] decreases:

  • When a slice is created, it points to an underlying array.
  • Slicing a slice does not allocate a new array. Instead, it creates a new slice value with a different pointer to the original array.
  • Changing the pointer effectively reassigns the slice to point to a different part of the underlying array. This can affect the capacity.

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