Does C Short-Circuit Evaluate the Logical AND Operator (&&)?

Short-Circuit Evaluation in C with &

When using the && operator in C , you may wonder if C short-circuits the evaluation of the expression. Does it evaluate the second operand even if the first operand evaluates to false?

Answer:

Yes, C indeed uses short-circuit evaluation with the && operator. If the first operand (bool1) evaluates to false, it doesn't bother evaluating the second operand (bool2).

Short-circuit evaluation optimizes the evaluation process by skipping unnecessary evaluations when the result can be determined from the first operand alone. This behavior is commonly referred to as "lazy evaluation."

The same short-circuiting applies to the || operator. If bool1 evaluates to true, the expression will evaluate to true without evaluating bool2.

If you need to evaluate both operands regardless of the first operand's value, you should use the & and | operators instead.

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