Home > Backend Development > Python Tutorial > Why Does My Seemingly Correct Python Code Throw a 'SyntaxError: Invalid Syntax'?

Why Does My Seemingly Correct Python Code Throw a 'SyntaxError: Invalid Syntax'?

Patricia Arquette
Release: 2024-12-18 10:12:11
Original
945 people have browsed it

Why Does My Seemingly Correct Python Code Throw a

Troubleshoot "SyntaxError: Invalid Syntax" in Seemingly Valid Python Code

When encountering a "SyntaxError: invalid syntax" error in a line of code that appears valid, it's prudent to check the preceding line. This error can potentially result from an imbalance of parentheses in the previous line, which can carry forward and trigger the error.

Consider the following code as an example:

fi2=0.460*scipy.sqrt(1-(Tr-0.566)**2/(0.434**2)+0.494)
guess = Pmin+(Pmax-Pmin)*((1-w**2)*fi1+(w**2)*fi2)
Copy after login

Here, the error is reported on line 2 for "invalid syntax." However, upon closer inspection, it becomes evident that line 1 has three open parentheses but only two closed parentheses.

open parentheses: 1  2  3        # count open parentheses
                   v  v  v       # forked lines leading to parentheses
fi2=0.460*scipy.sqrt(1-(Tr-0.566)**2/(0.434**2)+0.494)
                               ^   ^        # where error might be
closed parentheses:          1  2        # count closed parentheses
Copy after login

The erroneous line 1 should be corrected to:

fi2=0.460*scipy.sqrt(1-(Tr-0.566)**2/(0.434**2) + 0.494)  # add missing parenthesis
Copy after login

Note that in older versions of Python (pre-3.9), error messages were not as precise in identifying the location of the issue. However, in Python 3.9 and later, the error message correctly points to the source of the problem:

File "prog.py", line 1
    xyzzy = (1 +
            ^
SyntaxError: '(' was never closed
Copy after login

The above is the detailed content of Why Does My Seemingly Correct Python Code Throw a 'SyntaxError: Invalid Syntax'?. For more information, please follow other related articles on the PHP Chinese website!

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Latest Articles by Author
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template