How Can I Sort an Array of Random Integers in Java?

How to Sort an Array in Java: A Step-by-Step Guide

In this guide, we'll explore how to efficiently sort an array of randomly generated integers in Java. Let's delve into the provided code:

public static void main(String args[]) {
    int[] array = new int[10];

    // Populate the array with random values
    for (int i = 0; i < array.length; i++) {
        array[i] = ((int) (Math.random() * 100 + 1));
    }

    // Print the original array
    for (int i = 0; i < array.length; i++) {
        System.out.print(array[i] + " ");
    }
    System.out.println();

    // Sort the array
    Arrays.sort(array);

    // Print the sorted array
    for (int i = 0; i < array.length; i++) {
        System.out.print(array[i] + " ");
    }
}

Step 1: Populating the Array

An array is initialized with a size of 10, and each element is assigned a random integer between 1 and 100.

Step 2: Sorting the Array

To sort the array, we invoke the Arrays.sort() method. This utility method sorts the entire array in ascending order.

Step 3: Printing the Sorted Array

After sorting the array, it is printed to the screen, displaying the elements in ascending order.

Note: The original array is modified during sorting, so the printed original array will match the sorted version.

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