Does C 's Chained Comparison '(4 > y > 1)' Always Evaluate to False?

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Evaluating the Validity of Chained Logical Operators in C

The statement "(4 > y > 1)" raises questions about its validity and evaluation in C . Let's delve into these aspects and uncover how the statement behaves in C .

Expression Evaluation

The given statement can be broken down into its logical operators:

(4 > y) > 1

C evaluates chained logical operators from left to right. Therefore, the evaluation proceeds as follows:

1. Compare 4 and y: If y is less than 4, the result is 1 (true); otherwise, it's 0 (false).
2. Compare the result of step 1 and 1: Since the result of the first comparison (1 or 0) can never be greater than 1, the result of this comparison will always be false (0).

Implication:

The expression "(4 > y > 1)" is valid but always evaluates to false due to the logical flow explained above.

Exception:

One exception to this behavior is if y is an object of a custom class and the ">" operator has been overloaded to exhibit different behavior. In such a scenario, the result of the comparison can deviate from the typical numeric comparison rules.

Alternative Statement:

To provide clearer logical semantics, it's recommended to rewrite the expression as:

(4 > y && y > 1)

This formulation avoids the ambiguity of the original statement and correctly evaluates the conditions in the desired logical order.

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