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Why Does `console.log` Show Asynchronous Object Behavior?

Barbara Streisand
Release: 2024-12-20 03:28:14
Original
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Why Does `console.log` Show Asynchronous Object Behavior?

Asynchronous Behavior of Objects in Console.log

When examining objects using console.log, it's important to be aware of its asynchronous nature. Console receives an object reference synchronously but displays its properties only when it's expanded. This can lead to discrepancies if the object is modified before it's examined.

Consider the following code:

foo = [{id: 1},{id: 2},{id: 3},{id: 4}, {id: 5}, ];
console.log('foo1', foo, foo.length);
foo.splice(2, 1);
console.log('foo2', foo, foo.length);
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In Chrome, this produces the following output:

foo1 
[Object, Object, Object, Object, Object]  5
    0: Object
    1: Object
    2: Object
    3: Object
    length: 4
    __proto__: Array[0]
     5 (index):23
foo2 
[Object, Object, Object, Object]  4
    0: Object
    1: Object
    2: Object
    3: Object
    length: 4
    __proto__: Array[0]
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Initially, console.log receives a reference to the object foo. However, the properties are displayed later, after the object has been modified by foo.splice(2, 1). Hence, the output shows the updated values.

To mitigate this issue, there are several alternative logging approaches:

  • Log individual object values:
console.log(foo.id, foo.name, foo.age);
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  • JSON-encode the object as a string:
console.log(JSON.stringify(foo));
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  • JSON re-encode the object to maintain inspectability:
console.log(JSON.parse(JSON.stringify(foo)));
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These methods ensure that the logged output reflects the state of the object at the time of logging.

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