Problem:
Given a Spark SQL DataFrame with columns representing users, items, and user ratings, how can we group by user and then retrieve the top N items for each group using Scala?
Answer:
To achieve this, we can utilize the rank window function as follows:
import org.apache.spark.sql.expressions.Window import org.apache.spark.sql.functions.{rank, desc} val n: Int = ??? // Define the window specification val w = Window.partitionBy($"user").orderBy(desc("rating")) // Calculate the rank for each item val withRank = df.withColumn("rank", rank.over(w)) // Filter to retain only the top N items val topNPerUser = withRank.where($"rank" <= n)
Further Details:
If you prefer to use the row_number function, which assigns sequential row numbers rather than ranks (ignoring ties), you can replace rank with row_number in the window definition:
val w = Window.partitionBy($"user").orderBy(desc("rating")) val withRowNumber = df.withColumn("row_number", row_number.over(w)) val topNPerUser = withRowNumber.where($"row_number" <= n)
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