How to Unescape Java String Literals?
How to Unescape a Java String Literal in Java?
Java doesn't provide a straightforward function for unescaping string literals. This task requires manually converting character escape sequences into their corresponding characters.
Common Character Escapes
Escape Sequence | Character |
---|---|
Backslash | |
n | Newline |
r | Carriage return |
t | Tab |
b | Backspace |
f | Form feed |
" | Double quote |
' | Single quote |
Unescaping String Literals
One approach to unescape string literals is to use a custom function that iterates through the string, identifying escape sequences, and replacing them with the appropriate characters.
public static String unescape(String str) { StringBuilder sb = new StringBuilder(); for (int i = 0; i < str.length(); i++) { char c = str.charAt(i); if (c == '\') { i++; switch (str.charAt(i)) { case 'n': sb.append('\n'); break; case 'r': sb.append('\r'); break; case 't': sb.append('\t'); break; case 'b': sb.append('\b'); break; case 'f': sb.append('\f'); break; case '\"': sb.append('\"'); break; case '\'': sb.append('\''); break; case '\': sb.append('\'); break; default: sb.append(c); // Unrecognized escape sequence } } else { sb.append(c); } } return sb.toString(); }
Example:
String original = "\\"Hello, World!\\""; String unescaped = unescape(original); System.out.println(unescaped); // Output: "Hello, World!"
Libraries for String Unescaping
Some third-party libraries also provide functions for unescaping string literals. For example, the Apache Commons Lang library has the following method:
public static String unescapeJava(String str)
This method can be used to unescape Java string literals, including escape sequences not covered by the basic approach mentioned above.
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