How to Split a String in Java Using All Whitespace Characters as Delimiters?

How to Split a String Using All Whitespace Characters as Delimiters

When working with strings, it is often necessary to split them into substrings based on specific delimiters. In Java, the String.split() method can be used to perform this operation. By passing in a regular expression pattern, you can control how the string is divided.

For example, if you want to split a string using all whitespace characters (spaces, tabs, newlines, etc.) as delimiters, you would need to pass in the following regex pattern:

"\s+"

Detailed Explanation:

• The backslash () escapes the s character, indicating that it should be interpreted as a literal string, rather than as a special character.
• The s within the square brackets represents any whitespace character (space, tab, newline, etc.).
• The quantifier indicates that the preceding character (whitespace) can occur one or more times.

By combining these elements, the regex pattern "s " matches any sequence of one or more whitespace characters. When passed to the split() method, this pattern will cause the string to be split into substrings wherever there is a sequence of whitespace characters.

Example:

Consider the following string:

"Hello World\n\t\tGoodbye"

If we use the regex pattern "s " to split this string, we will get the following substrings:

["Hello", "World", "Goodbye"]

As you can see, the string has been split into substrings at every occurrence of one or more whitespace characters. The empty spaces between the first and second substrings and the second and third substrings have been omitted.

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