Splitting Strings on Any Whitespace Using Regex Patterns
To split a string using any whitespace character as a delimiter in Java, utilize the java.lang.String.split() method with an appropriate regex pattern.
The regex pattern to achieve this is \s . This pattern matches one or more occurrences of any whitespace character, such as spaces, tabs, newlines, etc.
Example:
Consider the following string:
myString = "Hello[space character][tab character]World"
Using the split() method with the pattern \s , we can split the string as follows:
String[] splitString = myString.split("\s+");
This will result in an array with two elements:
The split operation will ignore the whitespace characters between "Hello" and "World".
Escaping Backslashes:
Note that the backslash character in the regex pattern must be escaped in Java. This is because Java first tries to interpret escaped sequences, such as n for a newline. To escape the backslash, use \. Therefore, the final pattern becomes "\s ".
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