When encountering the error "Every derived table must have its own alias" in MySQL, it's crucial to delve into the concept of derived tables. These tables, also known as sub-queries, require an explicit alias to facilitate referencing within the outer query.
Let's take the example query causing the error:
SELECT ID FROM ( SELECT ID, msisdn FROM ( SELECT * FROM TT2 ) );
This query consists of two nested sub-queries. While the innermost sub-query retrieves data from the 'TT2' table, the error arises because both sub-queries lack an alias.
To rectify this error, each sub-query must be assigned a unique alias. The corrected query would resemble:
SELECT ID FROM ( SELECT ID, msisdn FROM ( SELECT * FROM TT2 ) AS T1 ) AS T2
Here, both sub-queries are assigned aliases ('T1' and 'T2'), allowing the outer query to reference their respective results.
In cases where the sub-query is simply extracting data from a table, the entire construct can be simplified.
SELECT ID FROM TT2
This streamlined query eliminates the sub-query layer while still achieving the desired result.
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