Accessing the subgroups captured by a regular expression in JavaScript can be achieved using the exec() method. This method returns an Array-like object containing the matches made by the expression.
To illustrate, consider the following example:
var myString = "something format_abc"; // Obtain "abc" const arr = /(?:^|\s)format_(.*?)(?:\s|$)/.exec(myString); console.log(arr); // Outputs: [" format_abc", "abc"] console.log(arr[1]); // Outputs: undefined (the issue) console.log(arr[0]); // Outputs: format_undefined (another issue)
The expected output is to obtain the subgroup "abc" as the second element of the arr array. However, accessing arr[1] and arr[0] leads to undefined and incorrect values, respectively.
Resolving the Undefined Output:
The lack of a value in arr[1] is due to the .*? non-greedy quantifier used in the regular expression. This quantifier captures the minimum number of characters possible, resulting in the string "format_abc" without the delimiter.
To fix this, use a greedy quantifier .* instead:
/(?:^|\s)format_(.*)(?:\s|$)/
Correcting the Incorrect String Output:
The arr[0] issue arises from the use of the console's printf-like formatting. The special character % in format_%A attempted to substitute the value of the next parameter, which was missing.
To fix this, escape the % in the regular expression:
/(?:^|\s)format_(.*?)(?:\s|$)/
With these modifications, the correct output is achieved:
[" format_abc", "abc"] console.log(arr[1]); // Outputs: "abc" console.log(arr[0]); // Outputs: " format_abc"
Accessing Matched Groups via matchAll() (ECMAScript 2020 and Later):
The String.prototype.matchAll() method provides a modern and more intuitive approach to iterating over multiple matches in a string. It returns an iterator that can be used as follows:
const string = "something format_abc"; const regexp = /(?:^|\s)format_(.*?)(?:\s|$)/g; const matches = string.matchAll(regexp); for (const match of matches) { console.log(match); console.log(match.index); }
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