Why Doesn't the `

Printing Function Pointers with << Operator

When attempting to print a function pointer using the << operator, one may encounter unexpected results. Converting the function pointer to a void* and using the printf function with the %p format successfully prints the desired value.

Function Pointer Interpretation by << Operator

The behavior of the << operator with an int (*)() function pointer is unexpected. In this case, the pointer is converted to a bool value, as defined by the C Standard's boolean conversion rule for pointers.

Output Behavior with void*

When a void* type is passed to the << operator, the contents of the pointer are printed in hexadecimal format. This is due to an overloaded version of the << operator designed specifically for void pointers.

Observing Member Function Pointers

Member function pointers cannot be directly printed using the << operator due to their complex structure. To observe the content of a member function pointer, an alternative method must be employed.

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