You have a string containing spaces between each word, and you want to remove these unnecessary whitespaces. The trim() function only removes leading and trailing whitespace, while replaceAll("\W", "") removes all non-word characters, including the equals sign (=).
To achieve the desired result, you can use the following regular expression-based replacement:
st.replaceAll("\s+", "")
This expression removes all consecutive whitespace characters (\s ) from the string. The quantifier matches one or more whitespace characters, effectively removing all spaces.
Alternatively, you can use the following simplified expression, which produces the same result:
st.replaceAll("\s", "")
This expression removes all single whitespace characters from the string.
While the second expression is slightly faster (approximately 20%), it's not as efficient as the first expression when dealing with large amounts of consecutive spaces. Therefore, for optimal performance, it's recommended to use st.replaceAll("\s ", "").
Remember to assign the updated string to a variable if you're not using it directly:
st = st.replaceAll("\s+", "")
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