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Why Does `open()` Fail with 'FileNotFoundError: No Such File or Directory'?

Susan Sarandon
Release: 2024-12-29 12:05:12
Original
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Why Does `open()` Fail with

FileNotFoundError: "No Such File or Directory" When Using open()

When attempting to open a file using open(), you may encounter the "FileNotFoundError: No Such File or Directory" error. This occurs when the specified file is not found in the expected location.

Python relies on two types of file paths:

  • Absolute Path: Begins with the root directory (e.g., C:Pythonscripts on Windows)
  • Relative Path: Relative to the current working directory

By default, Python treats paths as relative. So, when using open('file.txt'), it searches within the current working directory.

Diagnosing the Problem

  • Check if the file exists: Use os.listdir() to list files in the current working directory.
  • Confirm the current directory: Use os.getcwd() to display the current working directory.

Resolving the Error

There are two ways to resolve the error:

Method 1: Change Working Directory

  • Change the working directory to where the file is located using os.chdir().
  • Then, open the file using open('file.txt').

Method 2: Specify Absolute Path

  • Use an absolute path in the open() call.
  • For paths with backslashes on Windows, use a raw string (r"").

Additional Tips

  • Always ensure the file has the correct extension.
  • When specifying absolute paths, escape backslashes or use forward-slashes.
  • Example: open('C:/Folder/file.txt') or open(r'C:Folderfile.txt').

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