Home > Backend Development > PHP Tutorial > How Can I Properly Decode JSON into an Array Using `json_decode()`?

How Can I Properly Decode JSON into an Array Using `json_decode()`?

Linda Hamilton
Release: 2024-12-29 17:04:17
Original
468 people have browsed it

How Can I Properly Decode JSON into an Array Using `json_decode()`?

Dealing with the Enigma: Creating Arrays with json_decode()

Encountering the error "Fatal error: Cannot use object of type stdClass as array" while attempting to decode JSON into an array signifies a common misunderstanding. json_decode() defaults to creating an object, but arrays can be obtained by specifying the second argument as true.

Revisiting the Code:

The provided code below illustrates the problematic approach:

The Solution:

To resolve the issue, we simply need to provide true as the second argument to json_decode(), specifying our preference for an associative array rather than an object. The correct code would be:

Accessing Array Values:

Once you have your associative array, you can access its values using square brackets:

Integer Key Arrays:

If, however, you prefer integer keys instead of property names, you can achieve this by leveraging array_values():

Object Approach:

If you prefer to maintain the object structure, you can still access the desired property using the double arrow operator:

The above is the detailed content of How Can I Properly Decode JSON into an Array Using `json_decode()`?. For more information, please follow other related articles on the PHP Chinese website!

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Latest Articles by Author
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template