How Can I Find All Overlapping 10-Digit Number Series in a String Using Python's `re` Module?

Overlapping Regex Matches: Finding Every Series of Numbers

Introduction

The question arises of how to locate every overlapping 10-digit number series within a larger collection of numbers using the 're' module in Python 2.6. While non-overlapping matches are straightforward, extracting all occurrences proves challenging.

Solution

To address this problem, a capturing group can be employed within a lookahead. The lookahead identifies the desired sequences, but the actual match corresponds to the zero-width substring preceding it, ensuring non-overlapping matches.

Implementation

import re

s = "123456789123456789"
matches = re.finditer(r'(?=(\d{10}))', s)
results = [int(match.group(1)) for match in matches]

Output

[1234567891,
 2345678912,
 3456789123,
 4567891234,
 5678912345,
 6789123456,
 7891234567,
 8912345678,
 9123456789]

Explanation

The regular expression (?=(d{10})) asserts that immediately to its right is a capturing group representing a 10-digit numerical series (d{10}). The lookahead does not consume any characters, so the actual matches are the zero-length substrings preceding the lookaheads, which are the individual 10-digit series.

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