Does `break` Exit a `switch/select` or its Enclosing Loop in Go?

Does a break Statement Break from a Switch/Select or Escape the Loop It Resides in?

Many programming languages employ the switch/select statement to handle multiple cases, typically breaking automatically after each case execution. However, in Go, does a break statement within a switch/select statement solely terminate the switch/select block or cause an exit from the enclosing loop?

Answer:

In Go, a break statement exits the innermost for, switch, or select statement. If a label is provided, it must match the label of the enclosing loop, switch, or select construct.

The following excerpt from The Go Programming Language Specification clarifies this behavior:

Break statements, The Go Programming Language Specification.

A "break" statement terminates execution of the innermost "for",
"switch" or "select" statement.

BreakStmt = "break" [ Label ] .

Therefore, in the provided example:

for {
    switch sometest() {
    case 0:
        dosomething()
    case 1:
        break
    default:
        dosomethingelse()
    }
}

The break statement terminates only the switch statement, not the enclosing for loop.

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