Table of Contents
Array Assignment Syntax Outside of Declarations
Initializing with Array Literals
Initializing with the new Operator
Syntax Restrictions: Assigning Array Literals to Non-Declared Arrays
Workaround: Using new Operator with Array Literals
Example
Home Java javaTutorial How Does Java's Array Assignment Syntax Differ Inside and Outside of Declarations?

How Does Java's Array Assignment Syntax Differ Inside and Outside of Declarations?

Dec 30, 2024 am 03:10 AM

How Does Java's Array Assignment Syntax Differ Inside and Outside of Declarations?

Array Assignment Syntax Outside of Declarations

Java's array initialization syntax differs depending on whether it's used in a declaration or an assignment.

Initializing with Array Literals

When declaring an array, array literals can be used to initialize its elements:

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AClass[] array = {object1, object2};

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Initializing with the new Operator

Outside a declaration, arrays can be initialized using the new operator, followed by the element count and subsequent assignments:

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AClass[] array = new AClass[2];

array[0] = object1;

array[1] = object2;

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Syntax Restrictions: Assigning Array Literals to Non-Declared Arrays

However, attempting to assign an array literal to a non-declared array variable is prohibited:

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AClass[] array;

...

array = {object1, object2}; // Blocked by Java

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This restriction is imposed by Java for reasons that may not be immediately apparent.

Workaround: Using new Operator with Array Literals

As a workaround, the following syntax can be used:

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AClass[] array;

...

array = new AClass[]{object1, object2};

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This approach combines the array creation and initialization into a single statement while adhering to Java's syntax rules.

Example

For example, consider the following code snippet:

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public void selectedPointsToMove(cpVect coord) {

 

    if (tab == null) {

        if (arePointsClose(coord, point1, 10)) {

            cpVect[] tempTab = {point1};

            tab = tempTab;

        } else if (arePointsClose(point2, coord, 10)) {

            cpVect[] tempTab = {point2};

            tab = tempTab;

        } else {

            cpVect[] tempTab = {point1,point2};

            tab = tempTab;

        }

    }

}

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Without the workaround, the code would require additional statements to initialize tempTab before assigning it to tab.

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