Retrieving Week Number of Month in a Calendar Table
Determining the week number within a month is a crucial aspect of calendar management. This article addresses the challenge of adding this attribute to an existing calendar table.
To calculate the week number of a given date, the following steps can be taken:
In our case, we have a calendar table with the following schema:
CREATE TABLE [TCalendar] ( [TimeKey] [int] NOT NULL , [FullDateAlternateKey] [datetime] NOT NULL , [HolidayKey] [tinyint] NULL , [IsWeekDay] [tinyint] NULL , [DayNumberOfWeek] [tinyint] NULL , [EnglishDayNameOfWeek] [nvarchar] (10) COLLATE SQL_Latin1_General_CP1_CI_AS NULL , [SpanishDayNameOfWeek] [nvarchar] (10) COLLATE SQL_Latin1_General_CP1_CI_AS NULL , [FrenchDayNameOfWeek] [nvarchar] (10) COLLATE SQL_Latin1_General_CP1_CI_AS NULL , [DayNumberOfMonth] [tinyint] NULL , [DayNumberOfYear] [smallint] NULL , [WeekNumberOfYear] [tinyint] NULL , [EnglishMonthName] [nvarchar] (10) COLLATE SQL_Latin1_General_CP1_CI_AS NULL , [SpanishMonthName] [nvarchar] (10) COLLATE SQL_Latin1_General_CP1_CI_AS NULL , [FrenchMonthName] [nvarchar] (10) COLLATE SQL_Latin1_General_CP1_CI_AS NULL , [MonthNumberOfYear] [tinyint] NULL , [CalendarQuarter] [tinyint] NULL , [CalendarYear] [char] (4) COLLATE SQL_Latin1_General_CP1_CI_AS NULL , [CalendarSemester] [tinyint] NULL , [FiscalQuarter] [tinyint] NULL , [FiscalYear] [char] (4) COLLATE SQL_Latin1_General_CP1_CI_AS NULL , [FiscalSemester] [tinyint] NULL , [IsLastDayInMonth] [tinyint] NULL , CONSTRAINT [PK_TCalendar] PRIMARY KEY CLUSTERED ( [TimeKey] ) ON [PRIMARY] ) ON [PRIMARY]
To add the week number of month to this table, we can execute the following update statement:
update TCalendar set = WeekNumberOfMonth = DATEDIFF(week, DATEADD(MONTH, DATEDIFF(MONTH, 0, FullDateAlternateKey), 0), FullDateAlternateKey) +1
This query utilizes the DATEDIFF function to calculate the difference between the current date and the first day of the month (obtained using DATEADD). The resulting day number is then divided by 7 and incremented by 1 to determine the week number.
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