Parse First, Middle, and Last Name from Full Name Field using SQL
When processing data, it's often necessary to separate names into their constituent parts for easier manipulation. In this case, we need to extract the first, middle, and last names from a 'fullname' field while accounting for common data variations.
Efficient Solution with 90% Accuracy
The provided example provides a practical solution that handles most cases with a high degree of accuracy:
SELECT FIRST_NAME.ORIGINAL_INPUT_DATA, FIRST_NAME.TITLE, FIRST_NAME.FIRST_NAME, CASE WHEN 0 = CHARINDEX(' ', FIRST_NAME.REST_OF_NAME) THEN NULL -- No more spaces? Assume rest is last name ELSE SUBSTRING(FIRST_NAME.REST_OF_NAME, 1, CHARINDEX(' ', FIRST_NAME.REST_OF_NAME) - 1) END AS MIDDLE_NAME, SUBSTRING(FIRST_NAME.REST_OF_NAME, 1 + CHARINDEX(' ', FIRST_NAME.REST_OF_NAME), LEN(FIRST_NAME.REST_OF_NAME)) AS LAST_NAME FROM ( SELECT TITLE.TITLE, CASE WHEN 0 = CHARINDEX(' ', TITLE.REST_OF_NAME) THEN TITLE.REST_OF_NAME -- No space? Return the whole thing ELSE SUBSTRING(TITLE.REST_OF_NAME, 1, CHARINDEX(' ', TITLE.REST_OF_NAME) - 1) END AS FIRST_NAME, CASE WHEN 0 = CHARINDEX(' ', TITLE.REST_OF_NAME) THEN NULL -- No spaces at all? Then 1st name is all we have ELSE SUBSTRING(TITLE.REST_OF_NAME, CHARINDEX(' ', TITLE.REST_OF_NAME) + 1, LEN(TITLE.REST_OF_NAME)) END AS REST_OF_NAME, TITLE.ORIGINAL_INPUT_DATA FROM ( SELECT -- If the first three characters are in this list, -- then pull it as a "title". Otherwise return NULL for title. CASE WHEN SUBSTRING(TEST_DATA.FULL_NAME, 1, 3) IN ('MR ', 'MS ', 'DR ', 'MRS') THEN LTRIM(RTRIM(SUBSTRING(TEST_DATA.FULL_NAME, 1, 3))) ELSE NULL END AS TITLE, -- If you change the list, don't forget to change it here, too. CASE WHEN SUBSTRING(TEST_DATA.FULL_NAME, 1, 3) IN ('MR ', 'MS ', 'DR ', 'MRS') THEN LTRIM(RTRIM(SUBSTRING(TEST_DATA.FULL_NAME, 4, LEN(TEST_DATA.FULL_NAME)))) ELSE LTRIM(RTRIM(TEST_DATA.FULL_NAME)) END AS REST_OF_NAME, TEST_DATA.ORIGINAL_INPUT_DATA FROM ( SELECT -- Trim leading & trailing spaces before trying to process -- Disallow extra spaces *within* the name REPLACE(REPLACE(LTRIM(RTRIM(FULL_NAME)), ' ', ' '), ' ', ' ') AS FULL_NAME, FULL_NAME AS ORIGINAL_INPUT_DATA FROM ( -- Replace this block with your actual table SELECT 'GEORGE W BUSH' AS FULL_NAME UNION SELECT 'SUSAN B ANTHONY' AS FULL_NAME UNION SELECT 'ALEXANDER HAMILTON' AS FULL_NAME UNION SELECT 'OSAMA BIN LADEN JR' AS FULL_NAME UNION SELECT 'MARTIN J VAN BUREN SENIOR III' AS FULL_NAME UNION SELECT 'TOMMY' AS FULL_NAME UNION SELECT 'BILLY' AS FULL_NAME ) RAW_DATA ) TEST_DATA ) TITLE ) FIRST_NAME;
This query identifies and removes prefixes such as 'MR', 'MS', 'DR', and 'MRS' as separate 'TITLE' columns, handles missing names, multiple spaces in the name, and a single-part 'fullname' (first name only).
Handling Special Cases
The solution also includes a modification that addresses specific special cases, such as an empty 'fullname' field, trailing/leading spaces, multiple consecutive spaces, and a 'fullname' containing only the first name:
-- Handle the following special cases: -- 1 - The NAME field is NULL -- 2 - The NAME field contains leading / trailing spaces -- 3 - The NAME field has > 1 consecutive space within the name -- 4 - The NAME field contains ONLY the first name -- 5 - Include the original full name in the final output as a separate column, for readability -- 6 - Handle a specific list of prefixes as a separate "title" column SELECT FIRST_NAME.ORIGINAL_INPUT_DATA, FIRST_NAME.TITLE, FIRST_NAME.FIRST_NAME, CASE WHEN 0 = CHARINDEX(' ', FIRST_NAME.REST_OF_NAME) THEN NULL -- No more spaces? Assume rest is last name ELSE SUBSTRING(FIRST_NAME.REST_OF_NAME, 1, CHARINDEX(' ', FIRST_NAME.REST_OF_NAME) - 1) END AS MIDDLE_NAME, SUBSTRING(FIRST_NAME.REST_OF_NAME, 1 + CHARINDEX(' ', FIRST_NAME.REST_OF_NAME), LEN(FIRST_NAME.REST_OF_NAME)) AS LAST_NAME FROM ( SELECT TITLE.TITLE, CASE WHEN 0 = CHARINDEX(' ', TITLE.REST_OF_NAME) THEN TITLE.REST_OF_NAME -- No space? Return the whole thing ELSE SUBSTRING(TITLE.REST_OF_NAME, 1, CHARINDEX(' ', TITLE.REST_OF_NAME) - 1) END AS FIRST_NAME, CASE WHEN 0 = CHARINDEX(' ', TITLE.REST_OF_NAME) THEN NULL -- No spaces at all? Then 1st name is all we have ELSE SUBSTRING(TITLE.REST_OF_NAME, CHARINDEX(' ', TITLE.REST_OF_NAME) + 1, LEN(TITLE.REST_OF_NAME)) END AS REST_OF_NAME, TITLE.ORIGINAL_INPUT_DATA FROM ( SELECT -- If the first three characters are in this list, -- then pull it as a "title". Otherwise return NULL for title. CASE WHEN SUBSTRING(TEST_DATA.FULL_NAME, 1, 3) IN ('MR ', 'MS ', 'DR ', 'MRS') THEN LTRIM(RTRIM(SUBSTRING(TEST_DATA.FULL_NAME, 1, 3))) ELSE NULL END AS TITLE, -- If you change the list, don't forget to change it here, too. CASE WHEN SUBSTRING(TEST_DATA.FULL_NAME, 1, 3) IN ('MR ', 'MS ', 'DR ', 'MRS') THEN LTRIM(RTRIM(SUBSTRING(TEST_DATA.FULL_NAME, 4, LEN(TEST_DATA.FULL_NAME)))) ELSE LTRIM(RTRIM(TEST_DATA.FULL_NAME)) END AS REST_OF_NAME, TEST_DATA.ORIGINAL_INPUT_DATA FROM ( SELECT -- Trim leading & trailing spaces before trying to process -- Disallow extra spaces *within* the name REPLACE(REPLACE(LTRIM(RTRIM(FULL_NAME)), ' ', ' '), ' ', ' ') AS FULL_NAME, FULL_NAME AS ORIGINAL_INPUT_DATA FROM ( -- Replace this block with your actual table SELECT 'GEORGE W BUSH' AS FULL_NAME UNION SELECT 'SUSAN B ANTHONY' AS FULL_NAME UNION SELECT 'ALEXANDER HAMILTON' AS FULL_NAME UNION SELECT 'OSAMA BIN LADEN JR' AS FULL_NAME UNION SELECT 'MARTIN J VAN BUREN SENIOR III' AS FULL_NAME UNION SELECT 'TOMMY' AS FULL_NAME UNION SELECT 'BILLY' AS FULL_NAME UNION SELECT NULL AS FULL_NAME UNION SELECT ' ' AS FULL_NAME UNION SELECT ' JOHN JACOB SMITH' AS FULL_NAME UNION SELECT ' DR SANJAY GUPTA' AS FULL_NAME UNION SELECT 'DR JOHN S HOPKINS' AS FULL_NAME UNION SELECT ' MRS SUSAN ADAMS' AS FULL_NAME UNION SELECT ' MS AUGUSTA ADA KING ' AS FULL_NAME ) RAW_DATA ) TEST_DATA ) TITLE ) FIRST_NAME;
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